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3 years ago

What is the area of the triangle

Mathematics

1 answer:

zepelin [54]3 years ago

3 0

Answer:

60m^2 is the answer im pretty sure

Step-by-step explanation:

yeah man thats it

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Help, please I need it. I am horrible at math.

vivado [14]

B is the answer!!!!!!!!

8 0

3 years ago

There are eight furlongs in a mile and two weeks in a fortnight. if i travel 2800 furlongs in a fortnight, how many miles per da

yaroslaw [1]

The answer is 25 miles per day.

one mile = 8 furlongs
fortnight = 2 weeks = 14 days
convert furlongs to miles;
2800/8 = 350 miles
it means you travel 350 miles in 14 days
miles per day = 350/14 = 25
Thus, you travel 25 miles per day.

3 0

3 years ago

What is the best approximation for the area of the circle use 3.14 approximate pi<br> HELP PLZ

zysi [14]

Answer:

200.96

Step-by-step explanation:

Multiply the radius squared by pi. The radius is 8 in. so, 8 x 8 = 64. 64 x 3.14 = 200.96

Hope this helps!

4 0

4 years ago

Examine the diagram of circle C. Points Q, V, and W lie on circle C. Given that m∠VCW=97∘, what is the length of VW⌢?

8090 [49]

Answer:

$\frac{97pi}{18} m$

Step-by-step Explanation:

==>Given:

radius (r) = 10 m

m<VCW = 97°

==>Required:

Length of arc VW

==>Solution:

Formula for length VW is given as 2πr(θ/360)

Using the formula, Arc length = 2πr(θ/360), find the arc length VW in the given circle

Where,

θ = 97°

r = radius of the circle = 10 m

Thus,

Arc length VW = 2*π*10(97/360)

Arc length VW = 20π(97/360)

Arc length VW = π(97/18)

Arc length VW = 97π/18 m

Our answer is,

$\frac{97pi}{18} m$

8 0

4 years ago

The commute time for people in a city has an exponential distribution with an average of 0.5 hours. What is the probability that

mamaluj [8]

Answer:

0.314 = 31.4% probability that a randomly selected person in this city will have a commute time between 0.4 and 1 hours

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

In this question:

$m = 0.5, \mu = \frac{1}{0.5} = 2$

What is the probability that a randomly selected person in this city will have a commute time between 0.4 and 1 hours?

$P(0.4 \leq X \leq 1) = P(X \leq 1) - P(X \leq 0.4)$

In which

$P(X \leq 1) = 1 - e^{-2} = 0.8647$

$P(X \leq 0.4) = 1 - e^{-2*0.4} = 0.5507$

$P(0.4 \leq X \leq 1) = P(X \leq 1) - P(X \leq 0.4) = 0.8647 - 0.5507 = 0.314$

0.314 = 31.4% probability that a randomly selected person in this city will have a commute time between 0.4 and 1 hours

4 0

3 years ago