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Sauron [17]
3 years ago
15

Please help this is due tomorrow and I really don’t know how to do all I need is one answer and show work and tell me how you go

t your answer

Mathematics
1 answer:
Orlov [11]3 years ago
8 0

You should send a clearer picture. I have problems reading this.

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The equation 3x – 2y = 18 is in slope intercept
Gnoma [55]

Given:

The equation is:

3x-2y=18

To find:

The slope intercept form of the given equation.

Solution:

Slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

3x-2y=18

It is not in the slope intercept form.

We need to isolate variable y to get the slope intercept form.

The given equation can be rewritten as:

-2y=-3x+18

y=\dfrac{-3x+18}{-2}

y=\dfrac{-3x}{-2}+\dfrac{18}{-2}

y=\dfrac{3}{2}x-9

Therefore, the slope intercept form of the given equation is y=\dfrac{3}{2}x-9.

4 0
3 years ago
Create a linear equation in slope intercept form that contains the points (1,4) and (4,7).​
S_A_V [24]

Answer:

y = x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (4, 7)

m = \frac{7-4}{4-1} = \frac{3}{3} = 1, hence

y = x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation.

Using (1, 4), then

4 = 1 + c ⇒ c = 4 - 1 = 3

y = x + 3 ← equation in slope- intercept form

4 0
4 years ago
Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
3 years ago
In the equation y = 7x + 20, what is the slope or rate of change? 27 20 H 17 J X​
erma4kov [3.2K]
Answer
The slope is 7
5 0
3 years ago
Read 2 more answers
A clock is 17 minutes fast what is the correct time when it is showing 9:21 a.m.​
docker41 [41]

Answer:

9:04

Step-by-step explanation:

21 - 17 = 4

it's using subtraction

3 0
3 years ago
Read 2 more answers
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