Answer:
the greatest common factor is 2x^2
Answer:
√5
Step-by-step explanation:
We suppose the vertices are named clockwise around the top of the cube, then clockwise around the bottom (looking down from above the cube), with vertex E below vertex D. Then line AD is in plane ADEF, and line BM is in plane BCHG.
The distance between the named parallel planes is the distance between the lines. That distance is AB, which is given as √5.
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A diagram helps.
Please use " ^ " to indicate exponentiation. Then: <span>f(x) = (x – 3)^2 – 1.
By comparing this equation to y-k = (x-h)^2
you can see that h=3 and k= -1. Thus, the vertex is at (3, -1).
The axis of symm. goes thru the vertex, so is x = 3.
The domain is the set of all real numbers.
Since the vertex is (3, -1), the smallest value y can take on is -1. Thus, the range is [-1, infinity)
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The answer would be j=-3 If you want me to tell you how I got that answer just let me know :)
