All categories

3 years ago

What is the formula for volume

Mathematics

2 answers:

MrRissso [65]3 years ago

7 0

The formula for volume is v=lwh

dmitriy555 [2]3 years ago

4 0

Answer:length x width x hight=volume

Step-by-step explanation:

You might be interested in

A rectangular picture frame has a length that is 6 cm greater than the width. The total perimeter is 36

Elan Coil [88]

Answer:

Step-by-step explanation:

width= x

length= x+6

perimter = 2x+ 2(x+6)

36= 2x+ 2x+ 12

36= 4x + 12

36-12= 4x

4x= 24

x= 6

therefore width= 6cm

length= 6+6 = 12

3 0

3 years ago

Is 3.1 greater than 3 3/10

qaws [65]

Answer:

no, 3 3/10 is greater

Step-by-step explanation:

3.1 = 3 1/10 which is less than 3 3/10

6 0

3 years ago

Read 2 more answers

Li graphed the equation y=2x+3. Which table of values did Li use to create her graph?

Natali5045456 [20]

Answer:

See attached picture.

Step-by-step explanation:

To graph the line, start at (0,-3) since b=

-3 in the equation. This is the y-intercept.

Mark this point. From this point, move

down 2 units and to the right 1 unit. Mark

this new point at (1,-1). Connect the points

with a line. See attached picture.

8 0

2 years ago

What are Numbers? Why do we need them?

il63 [147K]

A number is a mathematical object used to count, measure, and label

3 0

3 years ago

A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe

e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= $^{31}P_5$

$=\dfrac{31!}{(31-5)!}$

$=\dfrac{31!}{(26)!}$

$=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}$

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= $^9P_2\times ^{22}P_3$

$= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}$

$= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}$

$= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}$

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

$= \dfrac{^{22}P_5 }{^{31}P_5}$

$= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }$

$= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}$

$= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}$

= 0.1549

≅ 0.155

4 0

3 years ago