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timurjin [86]
2 years ago
15

1:the area of a rectangular floor is 32m².if it's breadth is half of its length find its perimeter

Mathematics
2 answers:
forsale [732]2 years ago
7 0

\bold{\huge{\pink{\underline{ Solutions }}}}

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

  • <u>The </u><u>area </u><u>of </u><u>rectangular </u><u>floor </u><u>is </u><u>3</u><u>2</u><u> </u><u>m²</u>
  • <u>Breath </u><u>is </u><u>half </u><u>of </u><u>its </u><u>length </u>

<h3><u>Therefore</u><u>, </u></h3>

Let the length of the rectangular field be x

<u>So, </u>

Breath of the rectangular field will be x/2

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{\times{ Breath}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{32  = x }{\sf{\times{\dfrac{x}{2}}}}

\sf{32  =  }{\sf{\dfrac{x^{2}}{2}}}

\sf{ 32}\sf{\times{ 2 = x^{2}}}

\sf{ 64 = x^{2}}

\bold{ x = 8 m}

Thus, The length of rectanglular field is 8m

<u>Therefore</u><u>, </u>

Breath of the rectangular field will be

\sf{=}{\sf{\dfrac{8}{2}}}

\bold{ = 4 m }

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>perimeter </u><u>of </u><u>the </u><u>given </u><u>rectangular </u><u>field </u>

<u>We </u><u>know </u><u>that</u><u>, </u>

Perimeter of the reactangle

\bold{\blue{ = 2( L + W) }}

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>

Perimeter of the rectangular field

\sf{ = 2( 8 + 4) }

\sf{ = 2}{\sf{\times{12}}}

\bold{ = 24 m}

Hence, The perimeter of the rectangular field is 24 m

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u>

  • <u>The </u><u>perimeter </u><u>of </u><u>square </u><u>is </u><u>1</u><u>2</u><u> </u><u>cm</u>

Let the side of the square be x

<u>We</u><u> </u><u>know </u><u>that</u><u>, </u>

\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{\times{ side}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>

\sf{12  = 4 }{\sf{\times{ x }}}

\sf{\dfrac{ 12}{4}}{\sf{ = x }}

\bold{ x = 3 cm}

Thus, The length of the square is 3 cm

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u>

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\red{Area \: of \: square = Side }}{\bold{\red{\times{ Side}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of square

\sf{ = 3 }{\sf{\times{ 3 }}}

\sf{ = 9 cm^{2}}

Hence , The length and area of square is 3cm and 9 cm²

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u>

  • <u>The </u><u>perimeter</u><u> </u><u>of </u><u>square </u><u>feild </u><u>is </u><u>6</u><u>0</u><u> </u><u>m</u>

Let the side of the square feild be x

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{\times{ side}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{60  = 4 }{\sf{\times{ x }}}

\sf{\dfrac{ 60}{4}}{\sf{ = x }}

\bold{ x = 15 m }

Thus, The side of the square feild is 15m

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u>

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\red{Area \: of \: square = Side }}{\bold{\red{\times{ Side}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of square

\sf{ = 15  }{\sf{\times{ 15 }}}

\sf{ = 225 cm^{2}}

Hence, The area of square feild is 225 cm²

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

  • <u>The </u><u>perimeter </u><u>of </u><u>rectangle </u><u>is </u><u>2</u><u>8</u><u> </u><u>cm</u>
  • <u>The </u><u>length </u><u>of </u><u>rectangle </u><u>is </u><u>8</u><u> </u><u>cm</u>

Let the breath of the rectangle be x

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\blue{Perimeter\:of\: rectangle= 2( L + W) }}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 28 = 2( 8 + x) }

\sf{ 28 = 16 + 2x }

\sf{ 28 - 16 = 2x }

\sf{ 12 = 2x }

\sf{\dfrac{ 12}{2}}{\sf{ = x }}

\bold{ x = 6 cm}

Thus, The breath of the rectangle is 6 cm

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>rectangle </u>

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{\times{ Breath}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of rectangle

\sf{= 8 }{\sf{\times{6}}}

\sf{ = 48 cm^{2}}

Hence, The breath and area of rectangle is 6cm and 48 cm² .

[ Note :- Kindly refer app for better understanding ]

Bingel [31]2 years ago
3 0

Answer:

Step-by-step explanation:

1)  length = x m

breadth = x/2 m

Area of rectangular floor = 32 square m

length * breadth = 32\\\\x*\dfrac{1}{2}x = 32\\\\\\x^{2}=32*2\\\\\\x^{2} = 64\\\\x=\sqrt{64}=\sqrt{8*8}\\\\x = 8 \ m

Length = 8 m

Breadth =8/2 = 4 m

Perimeter = 2*(length + breadth) = 2*(8 + 4)

                = 2*12

                = 24 m

2) Perimeter of square = 12 cm

Side of a square = perimeter ÷ 4 = 12 ÷ 4 = 3 cm

Area =side *side = 3*3 = 9 cm²

3) Perimeter of square field = 60 m

Side = Perimeter ÷ 4 = 60 ÷4 = 15 m

Area of square = 15 * 15 = 225 m²

4) Perimeter of rectangle = 28 cm

breadth = (Perimeter ÷ 2) - length

             = (28 ÷2) - 8

             = 14 - 8

Breadth = 6 cm

Area of rectangle = 8 * 6 = 48 cm

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