Answer: D
Step-by-step explanation:
Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI = 
Thus,
Lower limit of CI = 
or
Lower limit of CI = 
or
Lower limit of CI = 98.11
and,
Upper limit of CI = 
or
Upper limit of CI = 
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F
A cell has a radius: r = 3 nmThe surface area of a cell:A = 4 r² π = 4 · 3² π = 4 · 9 π = 36 π nm²The volume of a cell:V = 4/3 r³ π = 4/3 · 3³ π = 4 · 9 π = 36 π nm³Answer: The surface area is 36 π nm² and the volume is 36 π nm³.
Answer:
144 feets
Step-by-step explanation:
Look on s(t) like quadratic function. We need to find maximum of the function using 1st diferetioal:
s(t)=-16t^2+64t+80
s’(t)=-32t+64
S’(t)=0 if t=2
For t>2, s’(t)<0
For t<2, s’(t)>0. So the maximum od function is in the point 2.
S(2)=-16*4+64*2+80=-64+128+80=144
Answer:
55+14=69
69x4=d
d=276
Step-by-step explanation:
its simple math really