Answer:
The proportion of former smokers with a university education is (A) 0.15
The proportion of men with a high school education that are current or former smokers is (B) 0.30
The degrees of freedom for the chi-square test for this two-way table are (B) 6
Step-by-step explanation:
The first thing to note is the two way table and ensure the proper arrangement of the figures in the table (Kindly find attached a picture of how the table should look)
Now, on to the first question on the former smokers with a university education = (43+28)/459 = 71/459 = 0.15 which is option A. [This is the total sum of former smokers with college and graduate school education].
The second question on the proportion of men with a high school education that are current or former smokers = (54+31+36)/459 = 0.285 = 0.30 (approximate value) which is option B.
The third question on the degrees of freedom for the chi-square test for this two-way table can be found with the formula DF = (r-1)(c-1) where,
DF = Degree of freedom ,
r = number of rows = 3
c = number of columns = 4 [<em>Kindly note that you have to exempt the row and columns with the totals</em>]
Therefore, DF = (3-1)(4-1) =2*3 = 6 which is option B.
2.7/3=0.9
it is less than one
Answer: 2 - 2*sin³(θ) - √1 -sin²(θ)
Step-by-step explanation: In the expression
cos(theta)*sin2(theta) − cos(theta)
sin (2θ) = 2 sin(θ)*cos(θ) ⇒ cos(θ)*2sin(θ)cos(θ) - cos(θ)
2cos²(θ)sin(θ) - cos(θ) if we use cos²(θ) = 1-sin²(θ)
2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)
2 - 2sin²(θ)sin(θ) - cos(θ) ⇒ 2-2sin³(θ)-cos(θ) ; cos(θ) = √1 -sin²(θ)
2 - 2*sin³(θ) - √1 -sin²(θ)
Answer:
3 1/4 inches
Step-by-step explanation:
22 3/4 ÷ 7
21÷7=3
1 3/4 = 7/4
7/4= 1/4+1/4+1/4+1/4+1/4+1/4+1/4
3 1/4 inches
<span>14554345555556675566669878 is your answer.
All you have to do when adding 1 is add the number at the very end of the number +1.
It's quite easy.
Glad I could help, and good luck!
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