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Ksju [112]
3 years ago
10

Use the net as an aid to compute the surface area of the triangular prism.

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0

Answer:

option D.

Step-by-step explanation:

Harrizon [31]3 years ago
4 0

Answer:

Option C. 564\ mm^{2}

Step-by-step explanation:

we know that

The surface area of the triangular prism using the net is equal to the area of two triangles plus the area of three rectangles

so

SA=2(\frac{1}{2})(10)(12)+2(13)(14)+(10)(14)

SA=60+364+140

SA=564\ mm^{2}

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P(5,6), -4x + 5y = 15 <br> into slope intercept form
Vaselesa [24]

Answer:

y = 4/5x - 3

Step-by-step explanation:

The slope-intercept form of a line is y = mx + b. We need to isolate the y.

(add 4x to 15)

-4x + 5y = 15

5y = 4x + 15

(divide by 5 from both sides)

y = 4/5x + 15/5

y = 4/5x + 3

8 0
3 years ago
Which is a possible turning point for the continuous
Ghella [55]

turning point of namely U-turn or vertex point, Check the picture below.

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2 years ago
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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Alik [6]

Answer:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

Step-by-step explanation:

Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:

X \sim Unif( a= 10100, b =14700)

If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

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8 0
3 years ago
Given that the measurement is in centimeters, find the area of the circle to the nearest tenth. (Use 3.14 for π)
coldgirl [10]
The area of a circle is equal to the radius squared times pie, basically:

{r}^{2} \times \pi

The radius is 3, so we multiply 3 times 3 times pie to get the area.

You're gonna want to plug in the following into a calculator:

3 \times 3 \times 3.14

After getting 28.26 from such calculator, you need to round to the tenths place. In this number, the tenths place is the 2 next to the decimal on the right. Because the number after the 2 is a 6, that means we need to simplify the answer to (28.3). When you are rounding a number, you look at the number to the right, if it is 5 or bigger, add one and remove the rest, if it is less than 5, just get rid of the rest and leave it as it is.
5 0
3 years ago
I need help with 11 and 12
Yakvenalex [24]

Answer:

Both are inverse pairs  

Step-by-step explanation:

Question 11

g(x)= 4 + \dfrac{8}{5}x

(a) Rename g(x) as y  

y = 4 + \dfrac{8}{5}x

(b) Solve for x :  

\dfrac{8}{5}x = y - 4

(c) Multiply each side by ⅝

x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}

(d) Switch x and y  

y = \dfrac{5}{8}x - \dfrac{5}{2}

(e) Rename y as the inverse function  

g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}

(f) Compare with your function

f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

 

Question 12

h(x)= x - 2

(a) Rename h(x) as y  

y = x - 2

(b) Solve for x:  

x = y + 2

(c) Switch x and y  

y  = x + 2

(e) Rename y as the inverse function  

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

5 0
3 years ago
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