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Iteru [2.4K]
2 years ago
9

When solving an equation in the form ax^2=c by taking square roots, how many solutions will there be?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
7 0
I think there would be two soulutions. ax^2 and c^2. Hope it's right. sorry if it is not. But hope it is and hope it helps.
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Which number line best represents he solution to the inequality -18x +3 <48?
Tanzania [10]

Answer: A

Step-by-step explanation:

Staar testtt

6 0
3 years ago
Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a
earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

<em><u>Solution:</u></em>

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

<em><u>Alex is 12 years older than George</u></em>

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

<em><u>Carl is Three times older than Alex</u></em>

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

<em><u>The sum of their ages is 68</u></em>

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

<em><u>Substitute eqn 1 and eqn 2 in eqn 3</u></em>

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

<em><u>Substitute a = 16 in eqn 2</u></em>

c = 3(16) = 48

c = 48

<em><u>Substitute a = 16 in eqn 1</u></em>

g = 16 - 12 = 4

g = 4

<em><u>Find the ratio of George’s age to Carl’s age to Alex’s age</u></em>

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

6 0
3 years ago
What is the correct answer
frozen [14]
43 g per eggs 
4 eggs weight are 172 g
so 1 egg weight is 172/4
                           = 43


7 0
3 years ago
Read 2 more answers
Please ASAP.
Flauer [41]

Answer:

2/3

Step-by-step explanation:

42/63 = 2/3

15/22.5 = 2/3

8 0
3 years ago
Read 2 more answers
In a particular faculty 60% of students are men and 40% are women. In a random sample of 50 students what is the probability tha
zimovet [89]

Answer:

a) The expected value is given by:

E(X) = np = 50*0.4 = 20

and the variance is given by:

Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12

b) P(X>25)= 1-P(X\leq 25)

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

P(X>25)= 1-P(X\leq 25)=0.0573

c) 1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

X \sim N(\mu = 20 , \sigma= 3.464)

d) P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z

e) P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=50, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

The expected value is given by:

E(X) = np = 50*0.4 = 20

and the variance is given by:

Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12

Part b

For this case we want to find this probability:

P(X>25)= 1-P(X\leq 25)

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

P(X>25)= 1-P(X\leq 25)=0.0573

Part c

1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

X \sim N(\mu = 20 , \sigma= 3.464)

Part d

We want this probability:

P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z

Part e

For this case we use the continuity correction and we have this:

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z

4 0
3 years ago
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