All categories

3 years ago

What cannot be performed using windows task manager

Computers and Technology

1 answer:

steposvetlana [31]3 years ago

3 0

Answer:

Window task manager cannot perform the following task:

1. It cannot Delete a program from hard disk.

2. It cannot view these application that are running at back ground.

3. It cannot recheck CPU usage

4. It cannot safe it self by virus.`

Read more about C++ programs here:

brainly.com/question/20339175

#SPJ1

3 0

2 years ago

Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera

zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

8 0

3 years ago

What is segmentation and paging?

iogann1982 [59]

Over the years, operating systems have sought to be more efficient, which is why it is vital that the use of main memory such as ram be as intelligent as possible, so that operating systems are more efficient.

Segmentation is a process of dividing the program into logical units, such as sub functions, arrays, variables, etc., making it possible to have processes divided into pieces so that it is easy to access each of the processes that this leads to its execution. Segmentation allows the programmer to contemplate the memory as if it had several address spaces or segments. References to memory consist of an address of the form segment number - offset.

Pagination is a technique where memory space is divided into physical sections of equal size, called page frames. The programs are divided into logical units, called pages, that are the same size as the page frames. In this way, an information page can be loaded in any page frame. The pages serve as an information storage unit and transfer between main memory and auxiliary or secondary memory. Each frame is identified by the frame address, which is in the physical position of the first word in the page frame.

8 0

3 years ago

Use the drop-down menu to complete the sentences about the benefits of flowcharts.

mojhsa [17]

Answer:

c,a,c using the drop down menus edge 2021

GOODLUCK

Explanation:

4 0

3 years ago

12. Write C statement(s) that accomplish the following. a. Declare int variables x and y. Initialize x to 25 and y to 18. b. Dec

saul85 [17]

Answer:

int x = 25;

int y = 18;

int temp = 10;

char ch ='a';

x += 5;

double payRate = 12.5;

int tempNum = firstNum;

int tempp = x;

x = y;

y = tempp;

printf("Value of x = %f\n",x);

printf("Value of y = %f\n",y);

printf("Arithmetic = %f\n",(x + 12/y -18));

char grade = 'A';

int a,b,c,d;

a = 5; b = 2; c = 3; d = 6;

int x = round(z);

Explanation:

The answers are straight forward.

However, I'll give a general hint in answering questions like this.

In C, variable declaration is done by:

data-type variable-name;

To declare and initialise the variable, you do;

data-type variable-name = value;

So, for questions that requires that we declare and initialise a variable, we make use of the above syntax..

Take (a) for instance:

int x = 25;

int y = 18;

Same syntax can be applied to (b), (d), (e), (h) & (I)

For question (c);

This can be done in two ways;

x = x + 5;

x+=5;

Both will give the same result.

For question (f):

We start by initialise a temporary variable that stores x.

Then we store the value of x in y.

Then we store the content of the temporary variable to y.

This swaps the values of x and y

For question (g):

When printing a double variable in C, we make use of '\f' as a string format

For question (j):

The round function is used to round up a double variable to integer.

3 0

3 years ago