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2 years ago

Angle A corresponds to Angle _____. B C E D none of the above

Mathematics

2 answers:

erastova [34]2 years ago

4 0

Answer:

the answer is B

kirza4 [7]2 years ago

3 0

Answer:

Angle A corresponds to Angle E (Choice 3)

Step-by-step explanation:

I just got this one on my lesson and got it right.

You might be interested in

Julie wrote the rate $108 in 6 weeks as a unit rate. Find her mistake and correct it.

Goshia [24]

Julie wants to express $108 in 6 weeks as a unit rate.

Her errors are:
$108 = $54 (Not true)
6 weeks = 3 weeks (Not true).

Instead,
$\frac{\$108}{6\,weeks} \\ = \frac{\$54 \times 2}{3\,weeks \times 2} \\ = \frac{\$54}{3\,weeks} \\ =18 \, \frac{\$}{week}$

The correct unit rate is 18 $/week.

6 0

3 years ago

The last time he checked, Matthew was 40 inches tall. Matthew just measured himself again and found out that he is 10% taller no

weqwewe [10]

44 inches.

All you have to do is find out what 10% of 40 is then add it back to 40. In the case of finding 10% of something you just “chop” of the back number (or move the decimal place forward) so 10% of 40 is 4. The. 40+4=44.

You can also multiply fractions to find the percent of a number but that is not necessary in this case.

8 0

3 years ago

Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).

Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

$m_1=\frac{7-0}{3-0}=\frac{7}{3}$

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)$

The slope of the line joining E(7,0), and F(3,7). is:

$m_1=\frac{7-0}{3-7}=-\frac{7}{4}$

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)$

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

4 0

2 years ago

Pls help me with this, (show work please) THANK YOU SO MUCH!!

den301095 [7]

D.) -20 degrees Fahrenheit because -12 degrees plus eight equals negative 20 degrees Fahrenheit

7 0

3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

2 years ago