Can someone please help me with my homework Ignore the bottom question
1 answer:
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Answer:
The correct answer is option b)
50a+10b<1000; 200a+360b < 7200; a> 0; b>0
Step-by-step explanation:
We are given that Two kind of crated cargo namely A and B to be shipped by truck.
<u>Cargo A:</u>
Volume of each crate of cargo A = 50 cubic ft
Weight of each crate of cargo A = 200 pounds
Let number of crates of cargo A to be shipped = a
Total volume of 'a' crates of cargo A = 50a cubic ft
Total weight of 'a' crates of cargo A = 200a pounds
<u>Cargo B:</u>
Volume of each crate of cargo B = 10 cubic ft
Weight of each crate of cargo B = 360 pounds
Let number of crates of cargo B to be shipped = b
Total volume of 'b' crates of cargo B = 10b cubic ft
Total weight of 'b' crates of cargo B = 360b
Total volume allowed in the truck is 1000 cubic ft
Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)
So, the inequality becomes
....... (1)
Total weight allowed (load limit) in the truck is 7200 pounds
Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)
So, the inequality becomes
....... (1)
And number of crates of cargo A and B are always a positive number.
So, a > 0 and b > 0.
So, the correct answer is option b.
<em>b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0</em>