All categories

3 years ago

While shopping at store, Billy

Mathematics

2 answers:

Anton [14]3 years ago

7 0

(900) .3 = 270
$900 30% = $270 discount

romanna [79]3 years ago

3 0

Answer:

A. 270

Step-by-step explanation:

30% can be rewritten as 3/10

To multiply 900 by 3/10, just divide by 10 (90) and multiply by 3 (270)

Therefore, the answer is A. 270

Bonus: To find the actual price, just subtract this amount (270) from the original price (900).

The television costs $630.

You might be interested in

Give full working and explanation

vlada-n [284]

Answer:

1309 marbles

Step-by-step explanation:

Kadon has 727 marbles.

Simon has: 727 - 145 = 582 marbles

All together:

Kadon marbles + Simon marbles

727 marbles + 582 marbles

1309 marbles

8 0

3 years ago

Can someone work out this problem for me because I do not get it and it is due tomorrow for homework? 83.971 + 10.9 PLSS HELPPPP

IrinaK [193]

If you are just adding those two decimals together, the answer would be 100.871.

83.971
+ 10.900 (make believe there are two zeros)
—————-
100.871

8 0

3 years ago

Read 2 more answers

System of equations <br> Elimination<br> please help i am stuck!!

Anika [276]

-5x = - 7 because -6x plus x is -5x and use elimination to get rid of the -3y so you end up with -5x = -7

7 0

3 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$