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Vilka [71]
3 years ago
15

What is 815 gal/hr blank qt/sec

Mathematics
1 answer:
viva [34]3 years ago
6 0
The answer is 163/180 quarts per second. Multiply 815 by 4 to get 3,260 quarts per hour. Then multiply 60 by 60 to get 3,260 quarts per 3,600 seconds. Divide 3,260 by 3,600 to get 163/180 quarts per second. 
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Write the rule for this pattern:2,4,7,14,17,34
Masja [62]

Answer:

The rule is x₁ = 2   x₂ = x₁ * 2    x₃ = x₂ + 3    x₄ = x₃ * 2    x₅ = x₄ + 3 ...

Step-by-step explanation:

Unable to use a single equation to define this sequence

The rule is x₁ = 2   x₂ = x₁ * 2    x₃ = x₂ + 3    x₄ = x₃ * 2    x₅ = x₄ + 3 ...

Multiply 2 then Plus 3 then multiply 2 then plus 3 ......

2,4,7,14,17,34, 37, 74, 77, 154....

6 0
3 years ago
How many solutions exist for -2|3x − 1| = 0?<br><br> A. 0<br> B. 1<br> C. 2<br> D. 3
Svetllana [295]

Answer:

B. 1

Step-by-step explanation:

-2|3x − 1| = 0

Divide by -2

|3x − 1| = 0

There is only one solution since 3x-1 must equal 0

3x = 1

x = 1/3

6 0
3 years ago
Read 2 more answers
In AMNO, m = 540 inches, n = 330 inches and o=600 inches. Find the measure of
MaRussiya [10]

Answer: 83.5

Step-by-step explanation:

5 0
3 years ago
Parallel lines cut by transversal?..help?
vagabundo [1.1K]

Answer:

#1

Step-by-step explanation:

6 0
3 years ago
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In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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