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olga nikolaevna [1]
2 years ago
11

Can someone help me figure this one out please?

Mathematics
1 answer:
Illusion [34]2 years ago
7 0

Answer:

Linear equations

Step-by-step explanation:

An easy and simple equation. F(t) = -15t +300

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Pls help me <br><br> Given the figure below, find the values of x and z.
gtnhenbr [62]

Step-by-step explanation:

the solution is in the picture

4 0
2 years ago
Read 2 more answers
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST AND 20 POINTS
Georgia [21]
1250 lbs of sand.

So first let's find the volume of the sand in the sandbox. You have a square sandbox, with a side length of 5, meaning you have a length and width of 5. You also have half a foot of sand in the sandbox, meaning that you have a height of 0.5. To find the volume of the sand, multiply the length by the width by the height:

5 * 5 * .5 = 12.5

So you have 12.5 cubic feet of sand. If each cubic foot of sand is 100 lbs, then you just multiply the two:

12.5 * 100 = 1250.0&#10;&#10;
6 0
3 years ago
Describe the transformation that moved Figure A to Figure B?
gavmur [86]

Answer:

D

Step-by-step explanation:

Its kinda hard to explain but its the answer

7 0
3 years ago
A woman starts out walking due north for 2 miles, and then she turns due west and continues for another 2 miles. How far from he
Mrac [35]
For this case we can model the problem as a rectangle triangle.
 We have:
 Length of the sides of the triangle.
 We want to find:
 Length of the hypotenuse.
 Using the Pythagorean theorem we have:
 d ^ 2 = 2 ^ 2 + 2 ^ 2&#10;
 d =  \sqrt{2 ^ 2 + 2 ^ 2} &#10;&#10;d =  \sqrt{4 + 4} &#10;&#10;d =  \sqrt{8} &#10;&#10;d =  2\sqrt{2} &#10;
 Answer:
 
She is:
 
d = 2\sqrt{2}
 miles far from her starting point
4 0
3 years ago
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