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choli [55]
4 years ago
9

The diameter of a ball is 8 in. What is the volume of the ball?

Mathematics
2 answers:
kati45 [8]4 years ago
6 0

Answer:

the correct answer is 267.95,i took the test

Step-by-step explanation:


ziro4ka [17]4 years ago
4 0
Given that the formula of a sphere is <span><span>V = 4/3 π r³
</span>Your answer would be 268.083 in.</span><span>³</span>
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tricia made 56% on her science test. if she got 14 problems correct, how many questions were on the test
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Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15
ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

Or even:

a_{n} = a_{m}r^{n-m}

The sum of the first n terms of a geometric sequence is given by:

S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}

Finding the common ratio:

a_{3} = 3.645, a_{8} = 15

a_{n} = a_{m}r^{n-m}

a_{8} = a_{3}r^{8-3}

a_{3}r^{5} = a_{8}

3.645r^{5} = 15

r^{5} = \frac{15}{3.645}

r = \sqrt[5]{\frac{15}{3.645}}

r = 1.327

Finding the first term:

a_{3} = a_{1}r^{2}

a_{1} = \frac{a_{3}}{r^{2}}

a_{1} = \frac{3.645}{(1.327)^{2}}

a_{1} = 2.07

Sum of the first nine terms:

S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44

The sum of the first nine terms of the sequence is 74.44.

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A square with sides of 7.6 m has an area of<br> meters squared.
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Step-by-step explanation:

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