Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
<h2>Volume Of Prism</h2>
Here is the base of a prism if the height of the prism is 5cm what is it’s surface area? what is it’s volume.
<h3>Solution:</h3>
- Volume = s²
- V = 5cm
- V = 5cm x 5cm
- V = 25cm²
- So The Surface area of Prism is 25cm².
#ProblemSolve
Answer:
46%
Step-by-step explanation:
You subtract the old by new then devide by the old and multiply by 100%
Let
x-------> the length side of the original cube
we have
Divide by 
both sides
The system of equations is equal to
--------> equation 
--------> equation
using a graphing tool
see the attached figure
we know that
the solution of the system of equations is the intersection both graphs
therefore
the solution is
therefore
<u>the answer is</u>
What are you trying to find?
