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zaharov [31]
2 years ago
5

I need help with this question​

Mathematics
1 answer:
eimsori [14]2 years ago
4 0

Answer:

No idea for this question

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To the nearest​ millimeter, a cell phone is 82 mm long and 36 mm wide. What is the ratio of the width to the​ length?
iVinArrow [24]
<h2>The ratio of the width to the​ length of a cell phone is 18 : 41.</h2>

Step-by-step explanation:

Given,

The length of a cell phone(l) = 82 mm  and

The width of a cell phone(b) = 36 mm

Find, the ratio of the width to the​ length of a cell phone = ?

∴ The ratio of the width to the​ length of a cell phone

= 36 mm : 82 mm

= 36 : 82

Divided by 2, we get

= \dfrac{36}{2} : \dfrac{82}{2}

= 18 : 41

Thus, the ratio of the width to the​ length of a cell phone is 18 : 41.

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3 years ago
What is an interval scale and what is it used for?
koban [17]
An interval scale has measurements where the difference between values is meaningful. For example, the year 0 doesn’t imply that time didn’t exist. And similarly, a temperature of zero doesn’t mean that temperature doesn’t exist at that point. Arbitrary zeros (and the inability to calculate ratios because of it) are one reason why the ratio scale — which does have meaningful zeros — is sometimes preferred.
8 0
3 years ago
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Can someone explain #1 and #2 to me? (Picture above) I really need help
Charra [1.4K]
A number can replaced with a variable like x
(X+3)4=16
4x+12=16
4x=4
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(X/4)+3=24
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Mary has a recipe for banana bread. She uses 712 cups of flour to make 3 loaves of banana bread. Andrea will follow the same rec
Softa [21]
237.3f= 1b. Explanation: is 712/3(237.3) so 1b is 237.3f
6 0
2 years ago
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Does anyone have the answers for all?
Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

<em><u>The order that works is second machine, then first machine.</u></em>

<u>Second Machine:</u>

y = (6)^{2} -6 = 36 - 6 = 30

Plug into first machine now.

<u>First Machine:</u>

y = \sqrt{(30) - 5}  = \sqrt{25} = 5

We see that the result is 5.

b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>

<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>

1-7. The absolute value of a value is the positive version of that value.

a. |54| = <em><u>54</u></em>

b. -|-7\frac{3}{5}| = -7\frac{3}{5}

c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>

d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>

1-8.

a.

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u>

<u>|  ||  ||  ||  ||  |</u>

<u>(5 boxes on each side)</u>

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u> <u>   </u>

<u>|  ||  ||  ||  ||  ||  |</u>

<u>(6 boxes on each side)</u>

b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>

c. <em><u>There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.</u></em>

1-9.

a. -42 - 17 = <em><u>-59</u></em>

b. 8 - (-9) = 8 + 9 = <em><u>17</u></em>

c. 8(-9) = <em><u>-72</u></em>

d. -42 ÷ (-7) = <em><u>6</u></em>

e. -2(-3)(-4) = 6(-4) = <em><u>24</u></em>

f. -18 - 7 = <em><u>-25</u></em>

g. (-5)^{2} = <em><u>25</u></em>

h. -5^{2}  = -(5)^2 = -(25) = <em><u>-25</u></em>

i. \sqrt{49} = <em><u>7</u></em>

1-10.  x = 2 Plug 2 in for x, then solve.

a. y = 7 - 3(2) = 7 - 6 = <em><u>1</u></em>

b. y = (2)^2 -1 = 4 - 1 = <em><u>3</u></em>

c. y = \frac{18}{2} = <em><u>9</u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

8 0
2 years ago
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