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yarga [219]
3 years ago
11

HELP..

Mathematics
1 answer:
qwelly [4]3 years ago
3 0
Answer:

The lines are parallel
You might be interested in
I have no idea what the answers are
lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
Similar polygons have corresponding sides that are proportional and corresponding angles that are -
Scorpion4ik [409]
A. congruent

hope this helped <33
6 0
3 years ago
A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r
svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, h^2 + b^2 = 16^2 = 256 \dotsc\;(1) because it is a right angle triangle.

It is given that \frac{db}{dt} = 1

Now differentiate (1) with respect to t (time) :

\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}

\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that 16 \sin{\theta} = b. When b = 8, then \theta = \arcsin{0.5} = \ang{30}.

Differentiate the above equation w.r.t t

\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}

c. The area of the triangle is given by A = 0.5\times h \times b. Differentiating w.r.t t,

\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}

Plugging in b = 8, h = 13.856, \frac{dh}{dt} = -0.588,

\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}

8 0
3 years ago
Find the nth term of 6,8,10,12
klemol [59]

Answer:

6 8 10 12 14 16 18 20 22

1 2. 3. 4. 5. 6. 7. 8. 9

4 0
2 years ago
Which expressions are equilvent to 1/36? Check all that apply
wel

Answer: 2/72

Step-by-step explanation:

1/36

(1*2)/(36*2)

2/72

3 0
3 years ago
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