I think it is two. I’m sorry if I am wrong.
Given
d(t)=-16t^2-4t+382
1. times at which rock is 310 from ground
solve d(t)=310=-16t^2-4t+382
=>
16t^2+4t-72=0
t=(-4+/-sqrt(4^2+4*16*72)/(2*16)
=> t=-9/4 or t=2
Reject negative root from context, so
time=2 seconds.
2.
maximum is when d'(t)=0, or
-32t-4=0 => t=-1/8
Therefore rock was descending since t=0 (can also see from -4t, i.e. initial velocity is -4 ft/s)
Rock reaches ground when d(t)=0, i.e.
-16t^2-4t+382=0
t=-5.01 or t=4.763 seconds. reject negative root.
Therefore, domain, t=0 to 4.763 seconds
range = 0 to 382 ft
Answer:
![y=4x](https://tex.z-dn.net/?f=y%3D4x)
Step-by-step explanation:
<u>Equation of the line</u>
A line can be expressed in many forms.
The equation of the line in slope-intercept form is:
y=mx+b
Being m the slope and b the y-intercept.
The point-slope form of the equation of a line is:
y-k=m(x-h)
Where m is the slope and (h,k) is a point through which the line passes.
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
![\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
We are required to find a line with slope m=4 passing through the origin (0,0).
Using the point-slope form:
y-0=4(x-0)
Simplifying
![\boxed{y=4x}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D4x%7D)
Answer:
The median is the average of all the numbers so you would first add all the numbers together which is 16+12+13+14+19+13+17+13=117
then you divide 117/8=14.6
Then your median is the middle number of all your numbers in numerical order
12, 13, 13, 13, 14, 16, 17, 19
which is 13 and 14, and between those two numbers is 13.5
Step-by-step explanation: