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Elena L [17]
3 years ago
12

Answer please I only need 3a and 3b ignore the rest

Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

The chocolates are<em> </em><u><em>heavier</em></u>  than the weight the weight stated on the label. And the chocolates are<em> </em><u><em>0.0042 pounds heavier</em></u>.

Step-by-step explanation:

Given:

Weight of the chocolates in the bag is labeled = 0.384 pounds.

The actual weight of the chocolates = 0.3798 pounds.

Now, to find is the chocolates are heavier or lighter than the weight stated on the label and how much it is heavier or lighter.

So, we see the that the weight labeled is 0.3840 pounds and the actual weight is 0.3798 pounds which is lighter than the weight in label. As we see the hundredth place of the decimal of the actual weight is 8 and the labeled weight is 7 which is less than 8.

<u><em>Thus, the chocolates are heavier than the weight the weight stated on the label.</em></u>

Now, to get how heavier it is, we subtract the label weight from the actual weight:

Actual\ weight\ -\ label\ weight.

=0.3840\ pounds\ -\ 0.3798\ pounds.

=0.0042\ pounds.

<u>So, the chocolates are 0.0042 pounds heavier</u>.

Therefore, the chocolates are heavier than the weight the weight stated on the label. And the chocolates are 0.0042 pounds heavier.

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3 years ago
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Perimeter of the carpet = 21.8 m

Area of the carpet = 29.4 $ m^{2}

<u>Given</u>:

<em>Dimension of the living room:</em>

<em />l = 4.9 $ m\\w = 6 $ m

<em>A. </em><em>Perimeter </em><em>of the carpet = perimeter of a </em><em>rectangle</em>

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Substitute

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Perimeter of the carpet = 21.8 m (The digits here are significant)

<em>B. </em><em>Area </em><em>of the carper = </em><em>area </em><em>of a </em><em>rectangle </em>

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Therefore, considering the rules of significant digits:

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brainly.com/question/12932084

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