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Elena L [17]
2 years ago
12

Answer please I only need 3a and 3b ignore the rest

Mathematics
1 answer:
babunello [35]2 years ago
5 0

Answer:

The chocolates are<em> </em><u><em>heavier</em></u>  than the weight the weight stated on the label. And the chocolates are<em> </em><u><em>0.0042 pounds heavier</em></u>.

Step-by-step explanation:

Given:

Weight of the chocolates in the bag is labeled = 0.384 pounds.

The actual weight of the chocolates = 0.3798 pounds.

Now, to find is the chocolates are heavier or lighter than the weight stated on the label and how much it is heavier or lighter.

So, we see the that the weight labeled is 0.3840 pounds and the actual weight is 0.3798 pounds which is lighter than the weight in label. As we see the hundredth place of the decimal of the actual weight is 8 and the labeled weight is 7 which is less than 8.

<u><em>Thus, the chocolates are heavier than the weight the weight stated on the label.</em></u>

Now, to get how heavier it is, we subtract the label weight from the actual weight:

Actual\ weight\ -\ label\ weight.

=0.3840\ pounds\ -\ 0.3798\ pounds.

=0.0042\ pounds.

<u>So, the chocolates are 0.0042 pounds heavier</u>.

Therefore, the chocolates are heavier than the weight the weight stated on the label. And the chocolates are 0.0042 pounds heavier.

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Consider the functions f(x) = 1
Lemur [1.5K]

Answer:

for both of the them the range geografeclly is 1 up

3 0
3 years ago
PLEASE ANSWER WITH ALL THE MATH
Colt1911 [192]

9514 1404 393

Answer:

  • Jacob: 4
  • his mother: 39

Step-by-step explanation:

Let J and M represent the current ages of Jacob and his Mother.

<u>currently</u>:

  M = 3 +9J

<u>in 11 years</u>:

  M+11 = 5 +3(J+11)

Using the first equation to substitute for M in the second, we have ...

  (3 +9J) +11 = 5 +3(J +11) . . . . . substitute for M

  9J +14 = 3J +38 . . . . . . simplify

  6J + 24 . . . . . . . . . . subtract 3J+14

  J = 4 . . . . . . . . . . divide by 6

  M = 3 +9(4) = 39

Jacob is 4 and his mother is 39.

8 0
2 years ago
How do you use a strategy of 30%of 900?
Julli [10]

Answer: 2 7 0

Step-by-step explanation:

1. We assume, that the number 900 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 900 is 100%, so we can write it down as 900=100%.

4. We know, that x is 30% of the output value, so we can write it down as x=30%.

5. Now we have two simple equations:

1) 900=100%

2) x=30%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

900/x=100%/30%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 30% of 900

900/x=100/30

(900/x)*x=(100/30)*x       - we multiply both sides of the equation by x

900=3.33333333333*x       - we divide both sides of the equation by (3.33333333333) to get x

900/3.33333333333=x

270=x

x=270

now we have:

30% of 900=270

3 0
3 years ago
1. What is the solution of n^2-49=0?
Effectus [21]

<u>Answer:</u>

<h2>1. a</h2><h2>2. b</h2><h2>3. b</h2><h2>4. b</h2><h2>5. 22</h2>

<u>Explanation:</u>

1.

n²-49=0

n=√49

n=7

2.

x²+64=0

x=√64

x=8

3.

if A=144x²

l = √A

l = √(144x²)

l = 12x

4.

b = (24×2)/3b

b = 48/3b

b = 16/b

b² = 16

b = √16

b = 4 in <em>(-4 is correct in algebra but there's no negative lengths in geometric shapes)</em>

5.

x²+z = 103

x² = 103-z

x = √(103-z)

for x = -9 and 9    (103-z) must equal 81

z = 103 - 81 = 22

x = √(103-22)

x = √81

x = -9 , 9

7 0
2 years ago
Need help with this fast
disa [49]

Answer:

\sf C. \quad 112 \pi \:units^2

Step-by-step explanation:

\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • radius = 4 units
  • height = 21 units

Substituting the given values into the formula:

\implies \sf Volume=\dfrac{1}{3} \cdot \pi \cdot 4^2 \cdot 21

\implies \sf Volume=112 \pi \:units^2

4 0
1 year ago
Read 2 more answers
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