In order for the triangle to be called an isosceles right triangle, it must satisfy both conditions: XZ and XY must be perpendicular to each other, and XZ = XY.
To determine whether two lines are perpendicular, their slopes must be negative reciprocals of each other.
Solving for the slopes of XZ and XY:
slope of XZ = (y₂-y₁) / (x₂-x₁) = (6-3)/(5-1) = 3/4
slope of XY = (y₂-y₁) / (x₂-x₁) = (3--1)/(1-4) = -4/3
-4/3 is the negative reciprocal of 3/4, therefore XZ and XY are perpendicular to each other.
Solving for distance:
XZ = √[(y₂-y₁)²+(x₂-x₁)²] = √[(6-3)²+(5-1)²] = 5
XY = √[(y₂-y₁)²+(x₂-x₁)²] = √[(3--1)²+(1-4)²] = 5
<span>The slope of XZ is 3/4, the slope of XY is -4/3, and XZ = XY = 5. </span>
Answer:
(2,1)
Step-by-step explanation:
one half of (4,2) would be (2,1)
easy math, just a little tricky logic
Answer:
4,847.2
Step-by-step explanation:
$8×30=$240
$240+3%=247.2
$4,600+247.2=4,847.2
Find common denominators for
and
:
Subtract: 3/6 - 2/6= 1/6
Therefore, your answer is
. Hoped I helped. :)
3^2 + 10^2 = 109
square root of 109 = 10.4403065089