Question

Find the first four terms of the sequence given by the following. an = 32+(n-1)-3, n=1, 2, 3...

Answer 1

The first four terms are 32,29,26,23

Step-by-step explanation:

Given sequence is:

$a_n=32+(n-1)(-3)$

We will put n=1,2,3,4

Putting n=1 in formula of sequence

$a_1=32+(1-1)(-3)\\=32+(0)(-3)\\=32+0\\=32$

Putting n=2

$a_2=32+(2-1)(-3)\\=32+(1)(-3)\\=32-3\\=29$

Putting n=3

$a_3=32+(3-1)(-3)\\=32+(2)(-3)\\=32-6\\=26$

Putting n=4

$a_4=32+(4-1)(-3)\\=32+(3)(-3)\\=32-9\\=23$

The first four terms are 32,29,26,23

Keywords: Arithmetic sequence, Recursive Formula

Learn more about arithmetic sequence at:

• brainly.com/question/10177389
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