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Dvinal [7]
2 years ago
13

Find the first four terms of the sequence given by the following. an = 32+(n-1)-3, n=1, 2, 3...

Mathematics
1 answer:
natta225 [31]2 years ago
5 0

The first four terms are 32,29,26,23

Step-by-step explanation:

Given sequence is:

a_n=32+(n-1)(-3)\\

We will put n=1,2,3,4

Putting n=1 in formula of sequence

a_1=32+(1-1)(-3)\\=32+(0)(-3)\\=32+0\\=32

Putting n=2

a_2=32+(2-1)(-3)\\=32+(1)(-3)\\=32-3\\=29

Putting n=3

a_3=32+(3-1)(-3)\\=32+(2)(-3)\\=32-6\\=26

Putting n=4

a_4=32+(4-1)(-3)\\=32+(3)(-3)\\=32-9\\=23

The first four terms are 32,29,26,23

Keywords: Arithmetic sequence, Recursive Formula

Learn more about arithmetic sequence at:

  • brainly.com/question/10177389
  • brainly.com/question/10427437

#LearnwithBrainly

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Step-by-step explanation:

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4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

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