Answer:
28
Step-by-step explanation:
28 = 7 x 4
So,
7 is a factor of 28.
Answer: 32
Step-by-step explanation:
1.) Write the initial equation: 2(9+7)
2.) Add the values in the parentheses: 2(16)
3.) Multiply the value in the parentheses by 2: 2(16) = 32
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Answer:
1) (f+g)(1) = e
2) (fg)(1) = 0
3) (3f)(1) = 3e
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Step-by-step explanation:
1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.
2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.
3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.
:)
Answer:
76
Step-by-step explanation:
recall that for a quadratic equation in the form
ax² + bx + c = 0, the discriminant is given by
discriminant, D = b²- 4ac
we are given the following:
-6x² + 2x + 3 = 0,
comparing this with the general equation above, it is clear that,
a = -6, b = 2 and c = 3,
substituting these into our equation for discriminant:
D = b²- 4ac
= 2² - 4(-6)(3)
= 4 + 72
= 76
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
