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Tanya [424]
3 years ago
11

Determine the rate and the unit rate. $18 for 6 volleyballs

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0

Answer:

3.00$ is the answer

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Billy collects 43x more than bob. Bob collects 37x more than shane. How much less does Shane collect than billy?
Anton [14]

Answer:

UUHH

Step-by-step explanation:

6 0
3 years ago
Quadrilateral ABCD ​ is inscribed in a circle.
Lerok [7]
In general, the sum of the measures of the interior angles of a quadrilateral is 360. This is true for every quadrilateral. This does not help here, because there are two angles (angles B and D) we know nothing about. We only know about opposite angles A and C.

In this case, you can use another theorem.
Opposite angles of an inscribed quadrilateral are supplementary.

m<A + m<C = 180

3x + 6 + x + 2 = 180

4x + 8 = 180

4x = 172

x = 43

m<A = 3x + 6 = 3(43) + 6 = 135

Answer: 135 deg
6 0
3 years ago
Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your
Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

#SPJ4

4 0
1 year ago
The model includes a new park in the center of the city. If the dimensions of the
11111nata11111 [884]

The question is incomplete. Here is the complete question.

As a part of city building refurbishment project,  architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.

The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?

Answer: 81 feet by 153 feet

Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.

In the refurbishment project, the unit scale is given by

1 inch = 9 feet

So, the dimensions of the new park in actual dimensions would be

1 inch = 9 feet

9 inches = x

x = 9.9

x = 81 feet

1 inch = 9 feet

17 inches = y

y = 17.9

y = 153 feet

The actual dimensions of the new park are 81 feet by 153 feet.

6 0
3 years ago
5,25,125 find 10th term
anastassius [24]

Answer:

9765625

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

r = 25 ÷ 5 = 125 ÷ 25 = 5

This indicates the sequence is geometric with n th term

a_{n} = a₁r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 5 and r = 5 , then

a₁₀ = 5 × 5^{9} = 5 × 1953125 = 9765625

6 0
3 years ago
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