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jeka94
3 years ago
14

Which line shows the first error in the solution

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

Step 4 is incorrect

Step-by-step explanation:

This is because you should divide 12 by 6 instead of multiplying.

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Jade says that the absolute value of a number and the opposite of a number is the same thing. Is Jade correct? Use examples to h
avanturin [10]

Answer:

No, the absolute value of a number is different from the opposite.

Step-by-step explanation:

For example, the absolute value of 4 is 4.

l4l = 4

But the opposite of 4 is -4.

Absolute value is ALWAYS positive, but the opposite of a positive number is a negative number.

8 0
3 years ago
Please help me with 16-20
jasenka [17]

Answer:

-4

Step-by-step explanation:

16-20 = -4

7 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of the equation?
SSSSS [86.1K]

Answer:

(a)

Step-by-step explanation:

To determine if the points are a solution to the equation.

Substitute the coordinates of the point into the left side of the equation and if equal to the right side then they are a solution.

(2, 5)

- 3(2) + 4(5) = - 6 + 20 = 14 ← True

(4, 6)

- 3(4) + 4(6) = - 12 + 24 = 12 ← False

Thus (2, 5) is the only solution to the equation → (a)

3 0
3 years ago
Write an equation of the line that passes through (-4,3) and (0,6).<br> An equation is y =
VMariaS [17]

Answer:

y= ¾x +6

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Let's find the gradient first.

gradient =  \frac{y1 - y2}{x1 - x2}

Using the formula above,

m =  \frac{6 - 3}{0 - ( - 4)}  \\ m = \frac{3}{4}

subst. the value of m into the equation.

y =  \frac{3}{4} x + c

To find c, substitute a coordinate.

When x=0, y=6,

6 =  \frac{3}{4} (0) + c \\ 6 = 0 + c \\ c = 6

Thus, the equation of the line is y =  \frac{3}{4} x + 6.

3 0
3 years ago
N divided by 5 plus 9 equals 22
jeka94
N/5 + 9 = 22

5(n/5 + 9 = 22)

n + 45 = 110

n = 65
3 0
3 years ago
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