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Nady [450]
2 years ago
14

3

Mathematics
2 answers:
noname [10]2 years ago
4 0

Answer:

Step-by-step explanation:

Did you mean  (y+4)^2 = 2?  " ^ " denotes exponentiation.

Expanding (y+4)^2 = 2, we get y^2 + 8y + 16 = 2, or

y^2 + 8y + 14 = 0

Let's apply the quadratic formula.  First, find the discriminant, b^2 - 4ac:

8^2 - 4(1)(14) = 64 - 56 = 8 (which is the square of 2√2).

Because the discriminant is positive, there are two real, unequal roots (solutions).  They are:

      -8 ± √8

x = -------------- = -4 ± √2

           2

shutvik [7]2 years ago
3 0
I believe the answer is y= -3
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If A+D=117kg , A+M=88kg and M+D=161kg whats there total weight<br><br>thx in advance
garri49 [273]
Think of A as a constant - with D it's 117 and with M it's 88

So the difference between D and M is 29   (117-88)

We also know that M + D = 161

Let's substitute in the problem  We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161  or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88   A + 61 - 88   Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)


6 0
3 years ago
Read 2 more answers
Let f(x) = xe−x if x ≥ 0 and f(x) = 0 if x &lt; 0<br> Is f a probability density function?
Lynna [10]

Yes. f(x) is a PDF if

• f(x) \ge 0 for all x in the support; this is true, since e^{-x}>0 for all x, and multiplying a positive number x doesn't change this fact;

• the integral of f(x) over its support is 1; this is also true, since

\displaystyle \int_{-\infty}^\infty f(x) \, dx = \int_0^\infty xe^{-x} \, dx = 1

which can be computed by parts.

3 0
1 year ago
Find the volume of the cone
kompoz [17]

Answer:

V≈628.32 units³

Step-by-step explanation:

I used the formula:

V=πr2h/3 (h/3 as in a fraction)

Hope this helps!

7 0
3 years ago
Read 2 more answers
How do you solve it?
Elis [28]

At heart we're being asked for a line through two points,


(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})


In general the line through (a,b) and (c,d) is


(y-b)(c-a)=(x-a)(d-b)


Check that you understand why both (a,b) and (c,d) are on this line.


Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,


(v - 355)(49 - 40) = (T - 40)(360 - 355)


9(v - 355) = 5(T - 40)


v-355 = \frac 5 9 T - \frac{200}{9}


v= \frac 5 9 T - \frac{200}{9} + 355


v= \frac 5 9 T + \frac{2995}{9}


That's our answer; let's check it.


When T=40, v = (5/9)40 + (2995/9) = 355 good


When T=49, v= (5/9)49 + (2995/9) = 360 good




7 0
3 years ago
Does anyone know how to solve this
Fofino [41]
Here is the answer the app is called cymath btw

3 0
3 years ago
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