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2 years ago

3

Mathematics

2 answers:

noname [10]2 years ago

4 0

Answer:

Step-by-step explanation:

Did you mean (y+4)^2 = 2? " ^ " denotes exponentiation.

Expanding (y+4)^2 = 2, we get y^2 + 8y + 16 = 2, or

y^2 + 8y + 14 = 0

Let's apply the quadratic formula. First, find the discriminant, b^2 - 4ac:

8^2 - 4(1)(14) = 64 - 56 = 8 (which is the square of 2√2).

Because the discriminant is positive, there are two real, unequal roots (solutions). They are:

-8 ± √8

x = -------------- = -4 ± √2

shutvik [7]2 years ago

3 0

I believe the answer is y= -3

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3 years ago

I REALLY NEED HELP PLEASE!!

disa [49]

part A)

$\bf \begin{array}{ccllll}
hours(x)&velocity(y)\\
-----&-----\\
1&6\\
3&2
\end{array}\\\\
-------------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ 2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
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\left. \qquad \right. \uparrow\\
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\\\\\\
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part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.

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Zigmanuir [339]

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answer
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Salsk061 [2.6K]

Answer:

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