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motikmotik
3 years ago
9

Find the slope of the line ​

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0
Can u upload pics bc we don’t know what the line is-
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8 cm<br> 10 cm<br> 3 cm<br> 12 cm<br> Work out the shaded area of the shape?
qwelly [4]

Answer:

36 sq. cm

Step-by-step explanation:

triangle area= 0.5 * 12* 10

rectangle are= 8* 3

60 - 24 = 36

6 0
3 years ago
Mark is purchasing new tiles for his bathrooms. The home improvement store charges $48 for each box of tiles when three or fewer
shutvik [7]

Answer:

f(x)=

1. 48x when x < or = 3,

2. 45x when 4 < or = x < or = 8

3. 42x when 9 < or = x < or = 19

4. 38x when x > 19

Step-by-step explanation:

3 boxes or less = Cost of tiles = $48

4 - 8 boxes ; cost = $45

9 - 19 boxes ; cost = $42

> 19 boxes ; cost = $38

6 0
1 year ago
Jermaine had dinner at his favorite restaurant. If the sales tax rate is 5% and the sales tax on the meal came to $2.00, what wa
galben [10]
I THINK ITS C I HOPE I HELPED!  :D
5 0
3 years ago
There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17
blondinia [14]

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

4 0
3 years ago
A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve
tester [92]

Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

As per the given condition:

Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



3 0
3 years ago
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