Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus = 
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) = 
Diagonal 1 (AC) = 
= 4 units
Diagonal 2(BD) = 
= 8 units
Now area of the rhombus ABCD = 
= 
= 16 units²
Therefore, area of the given rhombus is 16 units².
Answer:
Volume = 1596.2 cubic cm
Step-by-step explanation:
Volume = volume of box - volume of cylinder
Volume = (LxWxH) - 1/3 (pi * r^2 *h)
Volume = (10 x 12 x 20) -1/3 (3.14 x 8^2 x 12)
Volume = 2400 - 803.8
Volume = 1596.2 cm^3
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Answer:
I believe the answer is either going to be B or C
Step-by-step explanation:
The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
