What is the area of a regular pentagon with a radius of 6 cm?
1 answer:
Answer:
85.6 cm^2
Step-by-step explanation:
The area of the central triangle bounded by each of the sides can be computed as ...
A = (1/2)r²sin(α) . . . . where α is the central angle, 360°/5 = 72°
There are 5 such triangles, so the area of the pentagon is ...
A = (5/2)(6 cm)²sin(72°) ≈ 85.595 cm²
The area of the regular pentagon of radius 6 cm is about 85.6 cm².
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Answer:
2) -141 hits/da
Step-by-step explanation:
Calculate the values of h(2) and h(4)
h(2) = 2170(0.92)² = 2170 × 0.8464 = 1837
h(4) = 2170(0.92)⁴ = 2170 × 0.7164 = 1555
Calculate the average rate of change
Rate of change = (y₂ - y₁)/(x₂-x₁) = (1555 -1837)/(4 - 2) = -282/2 = -141 hits/da
The average rate of change is -141 hits/da.
In the figure below, the red curve represents the function h(d), while the green dashed line represents the average rate of change over the interval 2 ≤ d ≤4.
