3 years ago

What is the area of a regular pentagon with a radius of 6 cm?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

8 0

Answer:

85.6 cm^2

Step-by-step explanation:

The area of the central triangle bounded by each of the sides can be computed as ...

A = (1/2)r²sin(α) . . . . where α is the central angle, 360°/5 = 72°

There are 5 such triangles, so the area of the pentagon is ...

A = (5/2)(6 cm)²sin(72°) ≈ 85.595 cm²

The area of the regular pentagon of radius 6 cm is about 85.6 cm².

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Step-by-step explanation:

Let,

Quarters = x

Dimes = y

Pennies = z

We know that,

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Total amount = $6.60 = 6.60*100 = 660 cents

According to given statement;

25x+10y+z=660 Eqn 1

x=2z Eqn 2

y=z+5 Eqn 3

Putting these values of x and y in Eqn 1

$25(2z)+10(z+5)+z=660\\50z+10z+50+z=660\\61z=660-50\\61z=610\\$

Dividing both sides by 61;

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Putting z=10 in Eqn 2

$x=2(10)\\x=20$

Putting z=10 in Eqn 3

$y=10+5\\y=15$

He has 20 quarters, 15 dimes and 10 pennies.

Keywords: linear equations, substitution method

Learn more about linear equations at:

#LearnwithBrainly

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Marat540 [252]

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Step-by-step explanation:

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