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katovenus [111]
3 years ago
11

On a piece of paper use a protractor and ruler can instruct two equilateral triangles one with a side of length of 3 inches and

one with the side length of 4in which statement is true about the two triangles it is possible to construct equilateral triangles with the side lengths the two triangles are the same size and same shape these two triangles are the same shape but not the same size the two triangles are the same size but not the same shape
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

yes

Step-by-step explanation:    

1. put the compass at 3 inches

2. draw the arch mark at each end of the base line

4. put a dot were both arch marks intersect

5. draw a line connecting the triangle

6.repeat the following steps for the 4 inch triangle


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Answer:

circumference=50.24 cm

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Step-by-step explanation:

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area=πr^2=3.14×8²=200.96 cm²

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2

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Which of the following shows the graph of the inequality y &gt; –2x + 9?
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Trish is ordering t-shirts from a website that charges a certain amount per t-shirt plus a flat rate for shipping. The cost for
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20a. y = 8.75x - 5.99

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How many possible committees of 4 people can be chosen from 15 men and 20 women so that at least two women should be on each com
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<span>If there has to be 2 men and 2 women, we know that we must take a group of 2 men out of the group of 15 men and a group of 2 women out of the group of 20 women. Therefore, we have:

(15 choose 2) x (20 choose 2)


(15 choose 2) = 105

(20 choose 2) = 190

190*105 = 19950

Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>

 

<span>If there has to be 1 man and 3 women, we know that we must take a group of 1 man out of the group of 15 men and a group of 3 women out of the group of 20 women. Therefore, we have:

(15 choose 1) x (20 choose 3)


(15 choose 1) = 15

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15*1140 = 17100

Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>

 

<span>We now find the total outcomes of having a group with 4 women.

We know this is the same as saying (20 choose 4) = 4845</span>

Therefore, there are 4845 ways to have a group of 4 with 4 women.

 

We now add the outcomes of 2 women, 3 women, and 4 women and get the total ways that a committee can have at least 2 women.

 

19950 + 17100 + 4845 = 41895 ways that there will be at least 2 women in the committee


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