What is the instantaneous slope of y=-5\x at x=5
2 answers:
![y=-5x^{-1}](https://tex.z-dn.net/?f=y%3D-5x%5E%7B-1%7D)
![\frac{dy}{dx}=\frac{5}{x^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5Cfrac%7B5%7D%7Bx%5E%7B2%7D%7D)
The instantaneous slope at x = 5 is 1/5.
The answer is 1/5.
Answer:
Instantaneous slope is ![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Step-by-step explanation:
the instantaneous slope of y=-5\x at x=5
![y=\frac{-5}{x}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-5%7D%7Bx%7D)
To find instantaneous slope we take derivative of y
Derivative of 1/x is -1/x^2
![y'=\frac{5}{x^2}](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7B5%7D%7Bx%5E2%7D)
We need to find out instantaneous slope at x=5
so we plug in 5 for x in y'
![y'=\frac{5}{x^2}](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7B5%7D%7Bx%5E2%7D)
![y'=\frac{5}{5^2}](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7B5%7D%7B5%5E2%7D)
![y'=\frac{5}{25}](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7B5%7D%7B25%7D)
![y'=\frac{1}{5}](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7B1%7D%7B5%7D)
Instantaneous slope is ![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
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