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3 years ago

I need an answer and fast What happens if a sequence is out of order?

Computers and Technology

2 answers:

horsena [70]3 years ago

4 0

Answer:

i would say A

hope i helped <3

Explanation:

Virty [35]3 years ago

4 0

Answer:

a. The program may not work correctly.

Explanation:

I took the test :)

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State three positive uses of the computer in the government sector

WINSTONCH [101]

Well Here I got 4

1. Email Functions

2. Distributing Payments

3. Record Keeping

4. Direct Mail Promotions

<em>Have A great night!</em>

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3 years ago

What is Digital Access, and why is it important for YOUR generation?

Harman [31]

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2 years ago

Give a regular expression for binary numbers. They can be integers or binary fractions. A leading - sign is always allowed. Lead

Dmitry_Shevchenko [17]

Solution :

We have to provide an expression for the binary numbers. There can be binary fractions or integers. Whenever there is leading 0, it is not allowed unless the integer part is a 0.

Thus the expression is :

$(-+ \in )$ $[(1+10+11+100+101+110+111)(,000+,001+,010+,011+,111+,100+,101+,110)^*$ $(\in +.(0+1)^*(0+1))+(0.(0+1)^*(0+1))]$

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2 years ago

Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur

sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

for ip in range(octet_start, octet_end):

forth_octet = forth_octet + 1

if forth_octet > 255:

forth_octet = (forth_octet % 255) - 1

third_octet = third_octet + 1

if third_octet > 255:

third_octet = (third_octet % 255) - 1

second_octet = second_octet + 1

if second_octet > 255:

second_octet = (second_octet % 255) - 1

first_octet = first_octet + 1

if first_octet > 255:

print("No more available IP!")

break

print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0

3 years ago

What is typeface

Mademuasel [1]

I’m so bored and hungry answer is c 3566

4 0

2 years ago

Read 2 more answers