Answer:
Elevates rights to what you can access
Because it's getting info from the computer and presenting it to you. Similar in principle to a printer.
Answer: Stealth scanning technique
Explanation:
Stealth Scanning technique includes the following steps:
1. The client upon sending a single SYN packet to is responded by SYN/ACK packet if the port is open.
2. The port is assumed to be in closed state if the RST packe t is sent from the server.
3. This RST packet is sent by the client to close the initiation process so that a connection cannot be established.
Answer:
The answer is "Option C".
Explanation:
The local computer also refers to locally, it is a device, that is used by LAN. It is also called as a remote computer, in which all the data is stored in the main computer and accessible by protected password, and certain choices were wrong, which can be described as follows:
- In option A, It is used in digital communication.
- In option B, It is used in androids.
- In option D, It is used to provides web services.
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
