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3 years ago

HEEELLLPP PLEASEE I GIVE BRAINLIST!!!

Mathematics

1 answer:

Mila [183]3 years ago

4 0

Take any of the valid pairs of points, use the formula
rate of change = (y2-y1)/(x2-x1)

Say we use P1=(0,21.4), P2=(3,19)
x1=0, y1=21.4
x2=3, y2=19

Rate of change = (21.4-19)/(0-3)=2.4/(-3) = -0.8 sq. ft/in of liquid

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Show that x2 +x-3=0 has a solution between 1 and 2

Natali5045456 [20]

Answer:

here is the answer

Step-by-step explanation:

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7 0

3 years ago

Find the Surface Area of the prism please

rusak2 [61]

The surface area would be 33.6

5 0

2 years ago

About how many more inches of rain did Asheville get than Wichita? About how many more days did it rain in Asheville than Wichit

zaharov [31]

Answer:

Par 1) 19.10 inches

Part 2) 39 days

Step-by-step explanation:

we know that

Asheville

47.71 in

124 days

Wichita

28.61 in

85 days

Part 1) About how many more inches of rain did Asheville get than Wichita?

In this part subtract the number of inches of rain in Wichita from the number of inches of rain in Asheville

$47.71-28.61=19.10\ in$

Part 2) About how many more days did it rain in Asheville than Wichita?

n this part subtract the number of days of rain in Wichita from the number of days of rain in Asheville

$124-85=39\ days$

4 0

3 years ago

Please help me with this 50 points <br> Will marks brainliest

Natali [406]

$((( {64}^{ \frac{1}{2}})^{ \frac{1}{8}} )^{2} = \\$

$( {64}^{ \frac{1}{16} })^{2} = \\$

$(64)^{ \frac{1}{8}} = \\$

$( {2}^{6} )^{ \frac{1}{8} } = \\$

${2}^{ \frac{3}{4} } = \\$

$\sqrt[4]{2^{3} } = \\$

$\sqrt[4]{8}$

3 0

4 years ago

Find the vertical asymptote(s) of f (x) = StartFraction x squared minus 1 Over 2 x + 6 EndFraction.

viktelen [127]

<h2>Explanation:</h2>

We have the function:

$f(x)=\frac{x^2-1}{2x+6}$

The vertical asymptote can be found when the denominator equal zero, therefore:

$2x+6=0 \\ \\ 2x=-6 \\ \\ x=-3$

So the vertical asymptote occur at $x=-3$

3 0

3 years ago