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Y_Kistochka [10]
3 years ago
6

A bar of metal is cooling from 1000°C to room temperature, 22°C. The temperature, H, of the bar t minutes after it starts coolin

g is given, in °C, by H = 22 + 978e−0.1t.
Mathematics
1 answer:
NemiM [27]3 years ago
8 0
<span>Answer:
       I assume you're looking for a time-weighed average rather than just the [H(0) + H(60)]/2 average.
       Havg = (1/60)â«[20+980e^(-0.1t)]dt (evaluated from 0 to 60)
       Havg = (1/60)[20t - 98e^(-0.1t)] evaluated from 0 to 60
       Havg = (1/60)[20(60) - 98e^(-6) - 20(0) + 98e^(0)] = 1297.76/60 = 21.629 °C</span>
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una fracion reducicion a su minima expresion en igual a 1/8 . si la suma de sus terminos es 72. hallar la diferencia entre ellos
Mandarinka [93]

La diferencia entre el denominador y el númerador de la fracción es:

64 - 8 = 56.

<h3>¿Como encontrar la fracción?</h3>

Tendremos una fracción de la forma:

\frac{a}{b}

Tal que:

\frac{a}{b} = \frac{1}{8}

a + b = 72

Eso es un sistema de ecuaciones

Primero, podemos reescribir la primer ecuación como:

8a = b

Ahora podemos reemplazar "b" en la segunda ecuación por "8a", así obtenemos:

a + 8a = 72\\\\9a = 72\\\\a = 72/9 = 8

Ahora podemos obtener el valor de b:

b = 8a = 8*8 = 64

La diferencia entre a y b es:

b - a = 64 - 8 = 56

Sí quieres aprender m'as sobre sistemas de ecuaciones:

brainly.com/question/13729904

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2 years ago
Write an expression equivalent to 3(x-7)
maria [59]

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the temperature at dawn was -2°F during the day the temperature increased 15 degrees and then dropped 10 degrees in the evening
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If x is increased by 25% then, by what % is x² increased
Alinara [238K]

By <em>analytical</em> methods and <em>algebraic</em> handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

<h3>How to determine the percentage increase rate </h3>

In this case we have a <em>linear</em> variable x, whose increase is described by the following expression:

y = x · (1 + r/100)     (1)

Where r is the <em>increase</em> rate.

If we square (1), then we find that:

y² = x² · (1 + r/100)² = (1 + r'/100)     (2)

Where r' is the <em>equivalent increase</em> rate.

(1 + r/50 + r²/10000) = (1 + r'/100)

r'/100 = r/50 + r²/10000

r' = r/2 + r²/100

If we know that r = 25, then the equivalent increase rate is:

r' = 25/2 + 25²/100

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