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pav-90 [236]
3 years ago
13

Find the next four terms in the arithmetic sequence.

Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0

To find the arithmetic sequence, we can first find it's common difference by deducting the first term by the second term:

-7-(-15)

=-7+15

=8

Therefore the common difference is 8, and to find the remaining terms we can add 8 for the respective terms.

T(4) = 1+8 =9

Therefore the answer is c)9,17,25,33.

Hope it helps!

AfilCa [17]3 years ago
6 0

Answer: c) 9,17,25,33

Step-by-step explanation:

Use the equation a_n=a_1+d(n-1)

Where "n" is the nth term,  a_1 is the first term, "d" is the common difference and "n" is a integer greater than zero.

Find the common diference "d":

d=(-7)-(-15)\\d=8

Then we know that:

a_1=-15\\d=8\\

Since we need to find the next four terms and we know three terms then:

 For n=4:

a_4=-15+8(4-1))=9

For n=5:

a_5=-15+8(5-1))=17

For n=6:

a_6=-15+8(6-1))=25

For n=7:

a_7=-15+8(7-1))=33

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How many permutations of three items can be selected from a group of six? Use the letters A, B, C, D, E, and F to identify the i
pishuonlain [190]

Answer:

In total, 120 permutations of three items can be selected from a group of six distinct elements.

In particular, there are 6 ways to order three distinct items.

\begin{aligned}\rm B-D-F \\ \rm B-F-D \\ \rm D-B-F \\ \rm D-F-B \\ \rm F-B-D \\ \rm F-D-B\end{aligned}.

Step-by-step explanation:

The formula \displaystyle P(n,\, r) = \frac{n!}{(n - r)!} = n \, (n - 1) \cdots (n - r + 1) gives the number of ways to select and order r items from a group of n distinct elements.

To select and order three items from a group six distinct elements, let n = 6 and r = 3. Apply the formula:

\begin{aligned} P(6,\, 3) &= \frac{6!}{(6 - 3)!} = \frac{6!}{3!} \\ &= \frac{6 \times 5 \times 4 \times 3\times 2 \times 1}{3 \times 2 \times 1} \\ &= 6 \times 5 \times 4 = 120 \end{aligned}.

In other words, there are 120 unique ways to select and order three items (select a permutation of three items) from a group of six distinct elements.

Consider: what's the number of ways to order three distinct items? That's the same as asking: how many ways are there to select and order three items from a group of three distinct elements? Let n =3 and r = 3. Apply the formula for permutation:

\begin{aligned} P(3,\, 3) &= \frac{3!}{(3 - 3)!} = \frac{3!}{0!} && \left(\text{$0! = 1$ by convention.}\right) \\ &= 3! = 3 \times 2\times 1 \\ &= 6\end{aligned}.

To find the permutations, start by selecting one element as the first of the list. A tree diagram might be helpful. Refer to the attachment for an example.

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