Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
Lets try to solve out the problem,
Length = 3x-1
Width = x+1
Perimeter = 2(l+b)
Area = l*b
Perimeter= 2 (3x-1 + x+1)
P= 8x
Area = (3x-1) (x+1)
=> 3x(x+1) -1 (x+1)
=> 3x^2 + 3x -x -1
=> 3x^2 + 2x -1.
Hence Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
Learn more about Perimeter on:
brainly.com/question/397857
#SPJ4
Answer:
64
Step-by-step explanation:
2^2*2^4
4*16
=64
hope it helps
This problem is accompanied by a figure.
You can infere these relationships from the figure
(x-5)° = 74° => x = 74 + 5 = 79°
(x-5)° + 58° + (y-1)° = 180 ° => 74 + 58 + y-1 = 180 =>
y = 180 + 1 - 58 - 74 = 47°
Answer: x = 79°, y = 47°. This is the option d)
