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Anna007 [38]
3 years ago
12

Find the values of the variables in this kite. Enter your answer and show all the steps that you used to solve this problem.

Mathematics
1 answer:
guapka [62]3 years ago
5 0

<em>HERE'S</em><em> </em><em>YOUR</em><em> </em><em>ANSWER</em><em>.</em><em>.</em><em>.</em>

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The value of B is __ <br> The value of a
Advocard [28]

Answer:

The value of B is 11 times the value of a.

Step-by-step explanation:

a =|   2    |   4   |    7    |   10    |

b =|  22  |   44  |    77  |   110   |

22          44       77          110

÷2          ÷4        ÷7         ÷10

---------   --------   -------     ---------

11            11           11           11

I hope this helps!

5 0
2 years ago
Read 2 more answers
CORRECT ANSWER PLEASE!!!!! 150 points
juin [17]

Answer: -7

Step-by-step explanation:

First, lets use the functions to find the answer to f(-8) and g(4)

f(-8) is the same as asking for the value of y when x is -8

Therefore, f(-8) = -5 (according to the graph)

Using the same rule, g(4) would be the value of y when x = 4 which,

according to the graph, g(4) = 3

Plug these values back into the original equation to get:

-1*f(-8)-4*g(4)=?\\=-1*-5-4*3\\

using the order of operations, we will multiply the values first

(-1*-5)+(-4*3)\\=5+(-12)\\=5-12\\=-7

<h2>Therefore, our final answer is -7</h2>
4 0
2 years ago
Can someone please help me with math.
Nat2105 [25]

Answer:

I think -3

Step-by-step explanation:

3 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
What’s 9 + 10? Really struggling :(
____ [38]

21. Broooooo, This is baby stuff!

4 0
3 years ago
Read 2 more answers
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