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2 years ago

4. Determine the following for the equation y = vx – 1.

Mathematics

1 answer:

solniwko [45]2 years ago

6 0

Answer:

this isnt the answer but it helps solve the equation so here is a little explanation

Step-by-step explanation:

Cost Equation

-Is a mathematical equation for a straight line, to predict total cost.

-Total cost = total variable cost + total fixed cost or Y = vx + f

-Y = total mixed cost

v = variable cost per unit of activity

x = volume of activity

f = fixed cost over a given period of time

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2 years ago

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3 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

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3 years ago

I need the answer hurry plz

zaharov [31]

Answer:

350 ?

Step-by-step explanation:

500 - 150 = 350

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2 years ago