1/8 for the first one and second one is 23 times 6
Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Part 5)
Part 6) The graph in the attached figure
Step-by-step explanation:
Part 1) we have
![m=3/2=1.5](https://tex.z-dn.net/?f=m%3D3%2F2%3D1.5)
![point(-2,2)](https://tex.z-dn.net/?f=point%28-2%2C2%29)
The equation of the line into point slope form is equal to
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
substitute
![y-2=1.5(x+2)](https://tex.z-dn.net/?f=y-2%3D1.5%28x%2B2%29)
![y=1.5x+3+2](https://tex.z-dn.net/?f=y%3D1.5x%2B3%2B2)
![y=1.5x+5](https://tex.z-dn.net/?f=y%3D1.5x%2B5)
Part 2) we know that
If two lines are perpendicular
then
the product of their slopes is equal to minus one
so
![m1*m2=-1](https://tex.z-dn.net/?f=m1%2Am2%3D-1)
the slope of the line 1 is equal to
![m1=1.5](https://tex.z-dn.net/?f=m1%3D1.5)
Find the slope m2
![1.5*m2=-1](https://tex.z-dn.net/?f=1.5%2Am2%3D-1)
![m2=-2/3](https://tex.z-dn.net/?f=m2%3D-2%2F3)
Find the equation of the line 2
we have
![m2=-2/3](https://tex.z-dn.net/?f=m2%3D-2%2F3)
![point(-7,1)](https://tex.z-dn.net/?f=point%28-7%2C1%29)
The equation of the line into point slope form is equal to
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
substitute
![y-1=(-2/3)(x+7)](https://tex.z-dn.net/?f=y-1%3D%28-2%2F3%29%28x%2B7%29)
![y=-(2/3)x-(14/3)+1](https://tex.z-dn.net/?f=y%3D-%282%2F3%29x-%2814%2F3%29%2B1)
![y=-(2/3)x-(11/3)](https://tex.z-dn.net/?f=y%3D-%282%2F3%29x-%2811%2F3%29)
Part 3) we have
![m=1/4=0.25](https://tex.z-dn.net/?f=m%3D1%2F4%3D0.25)
The equation of the line into point slope form is equal to
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
substitute
![y-3=0.25(x-1)](https://tex.z-dn.net/?f=y-3%3D0.25%28x-1%29)
![y=0.25x-0.25+3](https://tex.z-dn.net/?f=y%3D0.25x-0.25%2B3)
![y=0.25x+2.75](https://tex.z-dn.net/?f=y%3D0.25x%2B2.75)
Part 4) we have
![m=-2](https://tex.z-dn.net/?f=m%3D-2)
-----> y-intercept
we know that
The equation of the line into slope intercept form is equal to
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
substitute the values
![y=-2x+5](https://tex.z-dn.net/?f=y%3D-2x%2B5)
Part 5) we have that
The slope of the line 4 is equal to ![-2](https://tex.z-dn.net/?f=-2)
so
the slope of the line perpendicular to the line 4 is equal to
![-2*m=-1\\m=(1/2)=0.5](https://tex.z-dn.net/?f=-2%2Am%3D-1%5C%5Cm%3D%281%2F2%29%3D0.5)
therefore
in this problem we have
![m=0.5](https://tex.z-dn.net/?f=m%3D0.5)
![point(-2,-2)](https://tex.z-dn.net/?f=point%28-2%2C-2%29)
The equation of the line into point slope form is equal to
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
substitute
![y+2=0.5(x+2)](https://tex.z-dn.net/?f=y%2B2%3D0.5%28x%2B2%29)
![y=0.5x+1-2](https://tex.z-dn.net/?f=y%3D0.5x%2B1-2)
![y=0.5x-1](https://tex.z-dn.net/?f=y%3D0.5x-1)
Part 6)
using a graphing tool
see the attached figure
There are 4 sets of 15 minutes in a hour so you would take the 10 airplanes and multiply it by 4 and get 40 as your answer
In 1 hour 40 planes with arrive at the airport
Answer:
a) 9
b) 8/7
c) 36/30
Step-by-step explanation:
Reciprocal is when the denominator and numerator "flip."
comment if you have any more questions :)