Ask question

Ask question

All categories

3 years ago

5

If I wanted to change the vertex of a quadratic function from (2,3) to (-1,6), what form would you use and what would you do to

it?

1 answer:

vampirchik [111]3 years ago

3 0

This is a translation and it is most easily done with the vertex from of the equation. change vertex to (-1,6): y=a(x+1)+6

You might be interested in

Geometry question on finding x.

Dmitrij [34]

Answer:

$x =63^o$

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

$\text{ $\overline{MN} $ and $\overline{ML}$ are tangents .}$

We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .

<u>According</u><u> to</u><u> question</u><u> </u><u>:</u><u>-</u><u> </u>

$\implies x + 117^o + 90^o +90^o = 360^o \\\\\implies x + 297^o = 360^o \\\\\implies x = 360^o - 297^o \\\\\implies x = 63^o$

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> x</u><u> </u><u>is </u><u>6</u><u>3</u><u>°</u><u> </u><u>.</u>

6 0

3 years ago

Graph the function by first finding its zeroes. <br> y = x3- 2x2 + x

CaHeK987 [17]

Answer:

The zeros of the function are;

x = 0 and x = 1

Step-by-step explanation:

The zeroes of the function simply imply that we find the values of x for which the corresponding value of y is 0.

We let y be 0 in the given equation;

y = x^3 - 2x^2 + x

x^3 - 2x^2 + x = 0

We factor out x since x appears in each term on the Left Hand Side;

x ( x^2 - 2x + 1) = 0

This implies that either;

x = 0 or

x^2 - 2x + 1 = 0

We can factorize the equation on the Left Hand Side by determining two numbers whose product is 1 and whose sum is -2. The two numbers by trial and error are found to be -1 and -1. We then replace the middle term by these two numbers;

x^2 -x -x +1 = 0

x(x-1) -1(x-1) = 0

(x-1)(x-1) = 0

x-1 = 0

x = 1

Therefore, the zeros of the function are;

x = 0 and x = 1

The graph of the function is as shown in the attachment below;

8 0

3 years ago

Select the correct answer from each drop-down menu.

finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be $(x_2,y_2)$

Coordinates of A = $(x_1,y_1)=(-6,5)$

Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

$x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}$

m:n=3:2

$3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\$

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

(fraction)

Let the coordinates of D be $(x,y)$

Coordinates of A = $(x_1,y_1)=(-6,5)$

Coordinates of B= $(x_2,y_2)=(10,-4)$

We will use section formula over here

$x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}$

m:n=3:2

$x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4$

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0

3 years ago

Simonne, Marco, and Evon were partners in

insens350 [35]

Evon got $450 .........

5 0

3 years ago

iogann1982 [59]

Answer:

THE ANSWER IS B

Step-by-step explanation:

NO EXPLANATION JUST TRUST ME

5 0

2 years ago