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posledela
3 years ago
10

Find an equation of the line perpendicular to Y equals 3X -3 and passes through the point -3 and -1

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

Answer:

y = - \frac{1}{3} x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3} , then

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (- 3, - 1) into the partial equation

- 1 = 1 + c ⇒ c = - 1 - 1 = - 2

y = - \frac{1}{3} x - 2 ← equation of perpendicular line

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Answer:

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Step-by-step explanation:

Given:

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For n=2 : f(3) = f(2) + 7 and so on.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder, which in this case is a 3, so what you is set the divisor underneath the remainder of 3. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², 2 becomes <em>2x</em><em>,</em><em> </em>and the remainder of 3 is set over the divisor, giving you the other factor of <em>x² + 2x + [3\x - 1]</em>.

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