Find an equation of the line perpendicular to Y equals 3X -3 and passes through the point -3 and -1

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

5 0

Answer:

y = - $\frac{1}{3}$ x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$ , then

y = - $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute (- 3, - 1) into the partial equation

- 1 = 1 + c ⇒ c = - 1 - 1 = - 2

y = - $\frac{1}{3}$ x - 2 ← equation of perpendicular line

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