Answer:
a, r = A sin (ωt±Ф) =5 Sin (3.9 t ± 2π) b. A e^-ωt = 5 e^-3.9 t
Step-by-step explanation:
ω =2πr/t =2π*5/8 =3.9 rad/sec, amplitude will be 5 (0, 5 )
The greatest common factor, or GCF, is quite self-explanatory. Between two numbers, you have to find the greatest number that can be divided by both numbers without any remainder. This is useful in solving addition and subtraction operations involving fractions. The technique to do this is to place the numbers to the right. Then, place the factors to the left. I'm gonna show the solution so that you can understand better.
4 | 12 28 24
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| 3 7 6
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Since all numbers can be divided by 4, you place it on the left side. Then, place the quotients on the next row below. Since, there is no more common factor, it ends with the 2nd row. Then, multiply all the left numbers with the numbers in the very last column.
GCF = 4×3×7×6
GCF = 504
Answer:
Jumping Jacks:7,<u>21,28</u>,42
Push-ups:2,6,8,<u>12</u>
Answer:
15/17
Step-by-step explanation:
if they won 2 games they lost 15 (17-2) so the ratio is 15/17
9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
