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Alecsey [184]
3 years ago
6

Given the functions f(x) = 3x − 1 and g(x) = 3x + 4, which operation results in the smallest coefficient on the x term?

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
Division because if you divide the two functions together, you keep the 3 in the x term. If you add the two functions, your coefficient is 6. If you subtract, the x term is eliminated. If you multiply, you'll get 9x.
3 is smaller than 6 or 9 :)
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How many solutions does this linear have y= 5x-1 -15x-3y=3?
musickatia [10]
-15x - 3y = 3

-15x - 3(5x-1) = 3 [input y]
-15x - 15x - 3 = 3 [distribute 3 over 5x and -1]
-30x - 3 = 3 [combine like terms]
-30x = 6 [add 3 to eliminate the negative]
x = \frac{6}{-30} [divide by -30 to get x alone]
x = \frac{1}{-5} [reduce the fraction]

Hopefully this is helpful enough to get you to your answer
4 0
2 years ago
The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards
jonny [76]
H = 3b+2
A = (h*b)/2     28 = (3b+2)b/2     56 = 3b²+2b    0 = 3b² + 2b - 56

⊕\left \{ {{y=2} \atop {x=2}} \right.  \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \beta  \\  \\  \\  x^{2}  \sqrt{x}  \sqrt[n]{x}  \frac{x}{y}  x_{123}  x^{123}  \leq  \geq  \pi  \alpha   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x_{123}  \int\limits^a_b {x} \, dx  \left \{ {{y=2} \atop {x=2}}
ω
 l
∩
8 0
3 years ago
Helppppppppppppppppppppppppp
kumpel [21]
Answer:
x = 10

Explanation:
Note the following rules before we begin:
2 ln(a) = ln (a²)
ln (a) + ln (b) = ln (ab)

Now, for the given:
ln(20) + ln(5) = 2 ln(x)
ln(20*5) = ln(x²)
ln(100) = ln(x²)

This means that:
100 = x²
Therefore:
either x = 10 .........> acceped
or x = -10 .........> rejected as no negatives are allowed within ln functions

Hope this helps :)
5 0
3 years ago
What is 25.5 as a fraction as well as 20.
motikmotik
53/2 is 25.5 as a fraction; 40/2 is 20 as a fraction
6 0
2 years ago
Read 2 more answers
find the surface areas of the larger cone and the smaller cone in terms of pi. compare the surface areas using a percent. (the m
serious [3.7K]

ANSWER :

Surface area of larger cone : 24π units^2

Surface area of smaller cone : 6π units^2

The surface area of the smaller cone is 25% of that of the larger cone.

EXPLANATION :

From the given problem,

AB = 3 is the radius of the larger cone and the slanted height is BC = 5

DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5

Recall the surface area of the cone :

A=\pi r^2+\pi rL

where r = radius and L = slanted height.

For the larger cone, r = 3 and L = 5

\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}

For the smaller cone, r = 1.5 and L = 2.5

\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}

Comparing the surface areas :

The area of the smaller cone compared to the larger cone is :

\begin{gathered} \frac{smaller}{larger}\times100=\frac{6\pi}{24\pi}\times100 \\  \\ =25\% \end{gathered}

3 0
1 year ago
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