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DENIUS [597]
3 years ago
14

The maintenance crew of a hotel has to monitor the temperature of the hotel pool and hot tub. To enhance comfort, the management

team requests that the mean pool temperature and the mean hot tub temperatures not differ by more than 15 degrees. To estimate the difference in these mean temperatures the maintenance crew selects a random sample of 8 times to check the hot tub temperature and a random sample of 10 times to check the pool temperature. Although the sample sizes are small, the distribution of temperature for the pool and for the hot tub does not show strong skewness or any outliers. The mean pool temperature is 86 degrees with a standard deviation of 3 degrees. The mean hot tub temperature is 101 with a standard deviation of 1.8 degrees. What is the correct 95% confidence interval for the true difference in the population means (hot tub – pool)? Use the conservative df.
Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer: Option D

Explanation: 100%

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Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost
Tju [1.3M]

The advance tickets were 35 in number and the same day ticket will be 30 in number.

<h3>What will be the number of tickets?</h3>

To find out the number of the tickets sold we will give some notations so the notations are as follows:-

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N_A= Number of the advance tickets

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The equations made by the given data will be:-

30N_A+15N_S=1500\\\\\\N_A+N_S=65

By solving the above equations:-

N_S=30\ \ \ \ \  \ N_A=35

Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.

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7 0
2 years ago
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Elena L [17]

Answer: hope it helps

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aliya0001 [1]
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3 0
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