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sertanlavr [38]
3 years ago
8

Mr. Smith's salary is $35,873.His wife salary is $32,870.what is their combined income?

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0
There combined in come would be <span>68,745 if you put them together i dont know if thats one of the awnsers but i think that should be right

</span>
kaheart [24]3 years ago
5 0
 $35,873
+ 32,870
 ------------ $68,743
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Perform the indicated operation. √75 + √12
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The answer is 7√3 and I'll tell you why


So the first step is to break down these big numbers to find a commen number like this:


√75= 5√3

√12= 2√3


Next you will just simply add the similar elements together:


5√3 + 2√3

5+2= 7


and so 7√3 is the correct answer

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Step-by-step explanation:

Binomial means that it will have two terms, so by process of elemination, we are only left with C and D. Degree would be the power, and D is the only one that has a power of 2.

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
nekit [7.7K]

Answer:

a) S= {HH, HT, TH, TT}

b) P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is 2^2 = 4

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

5 0
3 years ago
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