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4 years ago

Leslie rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:

Mathematics

2 answers:

ankoles [38]4 years ago

4 0

The only way to get an 11 is with a 5 and a 6 so the probability of rolling a sum of 11 is:

(2/6)(1/6)=2/36

Alexandra [31]4 years ago

3 0

Answer:

im not 100% but i think the answer is option a

Step-by-step explanation:

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Find all roots x^5-2x^3-8x=0

kobusy [5.1K]

X^5 - 2 x^3 - 8 x=0x (x - 2) (x + 2) (x^2 + 2) = 0
x - 2 = 0 or x = 0 or x + 2 = 0 or x^2 + 2 = 0
x = 2 or x = 0 or x = - 2 or x^2 = - 2
x^2 = - 2 has no solution since for all x on the real line, x^2 >= 0 and - 2 < 0

Ans : x = 2 or x = 0 or x = - 2

7 0

3 years ago

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Triss [41]

Answer:

December

Step-by-step explanation:

December: acoustic/ electric =10/12 = 5/6

January : 13/16

Get a common denominator of 48

5/6 *8/8 = 40/48 for December

13/16 * 3/3 =39/48 for January

December has a higher ratio

6 0

3 years ago

Ana has 296 coins in her coin collection. She

Step2247 [10]

Answer:

2,072

296 × 7 = 2,072

Step-by-step explanation:

...

3 0

3 years ago

What is 10.5% of 28?

lozanna [386]

Answer:

The answer is 2.94

Step-by-step explanation:

10.5x28 divided by 100=2.94

3 0

3 years ago

Square root of 144 X^7 Y^5

LekaFEV [45]

The first step to solving this is to factor out the first perfect square
$\sqrt{12^{2} x^{7} y^{5} }$
now factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{5} }$
then factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{4} X y}$
the root of a product is equal to the product of the roots of each factor
$\sqrt{ 12^{2} }$ $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the first square root
12 $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the second square root
12x³ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the third square root
12x³y² $\sqrt{xy}$
this means that the correct answer to your question is 12x³y² $\sqrt{xy}$ .
let me know if you have any further questions
:)

4 0

4 years ago