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statuscvo [17]
3 years ago
9

Grade 6 module 2 lesson 3 classwork 9/4 ÷ 3/4=

Mathematics
2 answers:
miskamm [114]3 years ago
6 0

Answer:

9/4 ÷ 3/4 = 3

Step-by-step explanation:

Brums [2.3K]3 years ago
6 0
(9/4)/(3/4)=3/1 since 4/4 is 1 and 9/3 is 3
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Tammy sells a car every 3rd day, and Henry sells a car every 5th day. If they both sell cars today, when is the next day that th
kolezko [41]

Answer:

the 2nd day

Step-by-step explanation:

took the test

5 0
3 years ago
Jupiter is 3 times the size of Neptune. If the diameter of Jupiter is 88,736 miles, what is the diameter of Neptune?
blagie [28]

Answer:

29,579 miles

Step-by-step explanation:

Divide Jupiter`s diameter by 3 which is 29,578.66 miles rounded up is 29,579 miles

4 0
3 years ago
What would be the equation for this graph? (WILL GIVE BRAINLEIST!)
ohaa [14]

Answer:

y = (x - 2)² - 9    Vertex form

y = x² - 4x - 5   Standard form

Step-by-step explanation:

vertex = (h, k) = (2, -9)

Vertex form

y = a(x - h)² + k

y = a(x - 2)² - 9

find "a" using point (5, 0)

0 = a(5 - 2)² - 9

0 = a(3)² - 9

0 = 9a - 9

9 = 9a

a = 1

y = (x - 2)² - 9

Standard form

y = (x² - 4x + 4)  - 9

y = x² - 4x - 5

6 0
3 years ago
Draw a bar model that shows how the number of hours in March compares with the number of hours in February of this year.
gogolik [260]
Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.

The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696

Now its time to graph

8 0
4 years ago
Read 2 more answers
For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
4 years ago
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