Answer:
Firstly we calculate the number of hours of both months.
This year is not a Leap year. So, the number of days of February is 28
and the number of days of March is 31
So, Number of hours February has 28 × 24 = 672 hours
and, Number of hours March has 31 × 24 = 744 hours
The bar graph is the best visual representation when we have categorical data. It is drawn by using a rectangular bar where the length of the bar represents height or frequency.
Answer:
$1,304.70
Step-by-step explanation:
If interest 6% annually, monthly is 0.5%.
The debt in 5 months will be 800 plus compounded interest for 5 months plus new due debt
In 3 more months the debt will be 2220.201 plus compounded interest for 3 months minus payment
After 8 months the debt would be 1253.67 plus compounded interest for 8 months
Then the size of the final payment would be $1,304.70
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
